How to check if a number is a perfect square in Python

In this article, we will learn to check if a number is a perfect square in python

Given below is the Python code to check if a number is a perfect square or not. The logic behind the code is that we are finding the square root of a number using the math.sqrt() function. Next, we check if the square root we obtained is an integer or not. If an integer, then the given number is a Perfect Square, else it is not.

import math 

def perfectSquarCheck(x): 

	# find floating point value of 
	# square root of x. 
	sr = math.sqrt(x) 

	# If square root is an integer 
	return ((sr - math.floor(sr)) == 0) 


nums = [4, 8, 16, 25, 100, 2500, 3225, 5000]
for i in nums:
	if (perfectSquarCheck(i)): 
		print(i, " is a Perfect Square") 
	else: 
		print(i, " is not a Perfect Square")

Output:

4  is a Perfect Square
8  is not a Perfect Square
16  is a Perfect Square
25  is a Perfect Square
100  is a Perfect Square
2500  is a Perfect Square
3225  is not a Perfect Square
5000  is not a Perfect Square